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英语
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培训
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dear povey， 亲爱的波维，
now i have a problem about the fst.i read fst.30.gz and read it in fstcopy. i am not sure the first and second rows is the trans-id.and the forth is the word-id.i do not understand the third row is what.if the first and second rows is state id,i am sure the third row is trans-id and the forth is word-id.but in our timit recipe in kaldi,it only have 48 phones and i see the si2022 have 20 phones,and the hmm trans-id is 6,so maybe trans-id.so i do not what means.thank you for your help. 现在我有一个关于fst.i的问题，我读取了fst.30.gz并在fstcopy中读取了它。我不确定第一列和第二列是“ trans-id”，第四列是单词“ id”。我不了解第三列是什么。如果第一列和第二列是状态id，我确定第三列是是trans-id，第四个是word-id。但是在我们的kaldi timit 脚本中，它只有48个音节，我看到si2022有20个音节，而hmm的trans-id是6，所以也许是对trans-id.so不理解。谢谢您的帮助。
best wishes, 最好的祝愿，
ben 本
faem0_si2022
0 1 2 0
1 2 4 0
1 1 1 0
2 3 6 0
2 2 3 0
3 4 2 38 0.693359
3 117 266 38 0.693359
3 3 5 0
4 115 4 0
4 4 1 0
5 6 268 0
6 7 270 0
6 6 267 0
7 8 2 0 0.693359
7 9 20 3 0.693359
7 7 269 0
8 113 4 0
8 8 1 0
9 10 22 0
9 9 19 0
10 11 24 0
10 10 21 0
11 12 2 0 0.693359
11 13 80 13 0.693359
11 11 23 0
12 111 4 0
12 12 1 0
13 14 82 0
13 13 79 0
14 15 84 0
14 14 81 0
15 16 2 0 0.693359
15 17 32 5 0.693359
15 15 83 0
16 109 4 0
16 16 1 0
17 18 34 0
17 17 31 0
18 19 36 0
18 18 33 0
19 20 2 0 0.693359
19 21 122 20 0.693359
19 19 35 0
20 107 4 0
20 20 1 0
21 22 124 0
21 21 121 0
22 23 126 0
22 22 123 0
23 24 2 0 0.693359
23 25 146 24 0.693359
23 23 125 0
24 105 4 0
24 24 1 0
25 26 148 0
25 25 145 0
26 27 150 0
26 26 147 0
27 28 2 0 0.693359
27 29 62 10 0.693359
27 27 149 0
28 103 4 0
28 28 1 0
29 30 64 0
29 29 61 0
30 31 66 0
30 30 63 0
31 32 2 0 0.693359
31 33 68 11 0.693359
31 31 65 0
32 101 4 0
32 32 1 0
33 34 70 0
33 33 67 0
34 35 72 0
34 34 69 0
35 36 2 0 0.693359
35 37 242 41 0.693359
35 35 71 0
36 99 4 0
36 36 1 0
37 38 244 0
37 37 241 0
38 39 246 0
38 38 243 0
39 40 2 0 0.693359
39 41 224 37 0.693359
39 39 245 0
40 97 4 0
40 40 1 0
41 42 226 0
41 41 223 0
42 43 228 0
42 42 225 0
43 44 2 0 0.693359
43 45 152 25 0.693359
43 43 227 0
44 95 4 0
44 44 1 0
45 46 154 0
45 45 151 0
46 47 156 0
46 46 153 0
47 48 2 0 0.693359
47 49 260 44 0.693359
47 47 155 0
48 93 4 0
48 48 1 0
49 50 262 0
49 49 259 0
50 51 264 0
50 50 261 0
51 52 2 0 0.693359
51 53 68 11 0.693359
51 51 263 0
52 91 4 0
52 52 1 0
53 54 70 0
53 53 67 0
54 55 72 0
54 54 69 0
55 56 2 0 0.693359
55 57 212 35 0.693359
55 55 71 0
56 89 4 0
56 56 1 0
57 58 214 0
57 57 211 0
58 59 216 0
58 58 213 0
59 60 2 0 0.693359
59 61 44 7 0.693359
59 59 215 0
60 87 4 0
60 60 1 0
61 62 46 0
61 61 43 0
62 63 48 0
62 62 45 0
63 64 2 0 0.693359
63 65 254 43 0.693359
63 63 47 0
64 85 4 0
64 64 1 0
65 66 256 0
65 65 253 0
66 67 258 0
66 66 255 0
67 68 2 0 0.693359
67 69 122 20 0.693359
67 67 257 0
68 83 4 0
68 68 1 0
69 70 124 0
69 69 121 0
70 71 126 0
70 70 123 0
71 72 2 0 0.693359
71 73 26 4 0.693359
71 71 125 0
72 81 4 0
72 72 1 0
73 74 28 0
73 73 25 0
74 75 30 0
74 74 27 0
75 76 2 0
75 75 29 0
76 77 4 0
76 76 1 0
77 78 6 0
77 77 3 0
78 79 2 38 0.693359
78 118 0 38 0.693359
78 78 5 0
79 80 4 0
79 79 1 0
80 119 6 0
80 80 3 0
81 82 6 0
81 81 3 0
82 73 26 4
82 82 5 0
83 84 6 0
83 83 3 0
84 69 122 20
84 84 5 0
85 86 6 0
85 85 3 0
86 65 254 43
86 86 5 0
87 88 6 0
87 87 3 0
88 61 44 7
88 88 5 0
89 90 6 0
89 89 3 0
90 57 212 35
90 90 5 0
91 92 6 0
91 91 3 0
92 53 68 11
92 92 5 0
93 94 6 0
93 93 3 0
94 49 260 44
94 94 5 0
95 96 6 0
95 95 3 0
96 45 152 25
96 96 5 0
97 98 6 0
97 97 3 0
98 41 224 37
98 98 5 0
99 100 6 0
99 99 3 0
100 37 242 41
100 100 5 0
101 102 6 0
101 101 3 0
102 33 68 11
102 102 5 0
103 104 6 0
103 103 3 0
104 29 62 10
104 104 5 0
105 106 6 0
105 105 3 0
106 25 146 24
106 106 5 0
107 108 6 0
107 107 3 0
108 21 122 20
108 108 5 0
109 110 6 0
109 109 3 0
110 17 32 5
110 110 5 0
111 112 6 0
111 111 3 0
112 13 80 13
112 112 5 0
113 114 6 0
113 113 3 0
114 9 20 3
114 114 5 0
115 116 6 0
115 115 3 0
116 120 266 45
116 116 5 0
117 5 0 45
117 117 265 0
118
119 118 0 0
119 119 5 0
120 5 0 0
120 120 265 0It looks like this is the acceptor format of OpenFst. The 3rd field
is the word-id and the last field is the cost (negated
log-likelihood), coming from the lexicon (pron-prob of
silence/not-silence).
看起来这是OpenFst的接受者格式。第三列是word-id且最后一列是成本（否定对数似然性），来自lexicon（沉默/不沉默的问题概率）
dear povey, 亲爱的波维，
thank you for your reply.but it have five rows.the fifth rows is cost,but always
empty.the forth is word-id.because in timit,the word.txt is the same as the lexcious.txt and phone.txt,and it only no more than 50.so i am not sure what is it.
thank you for your reply again. 谢谢您的答复。但它有五列。第五列是费用，但总是空的。第四个是word-id。因为很简单，word.txt与lexcious.txt和phone.txt相同，并且最多不超过50个。所以我不确定这是什么。
best wishes, 再次感谢您的回复。
ben 最好的祝愿，
Oh, I see, this is a per-utterance decoding graph. The inputs are transition-ids. 哦，我知道了，这是每个发音的解码图。输入是transition-id。
yes,it is a per-utterance decoding graph.you means the third rows is transition-id?and the first and second rows is also transition-id? 是的，这是一个基于语音的解码图。您的意思是第三列是transition-id？而第一列和第二列也是transition-id？
ben 本
First and second rows are begin/end state in the FST; see www.openfst.org to understand the FST format. 第一和第二列是FST中的开始/结束状态；看
i know it .but in timit,every HMM is have 3 states.and this utterance is 20 phones.so the first and second rows should be no more than 60,but the first and second rows is 120 now.so i do not know that. 我知道。但是在timit中，每个HMM都有3个状态。这种话语是20个音节。所以第一和第二列应该不超过60，但是现在第一和第二列是120。所以我不知道那。